You are currently viewing Derivative of e^x using First Principle of Derivatives
Derivative of e^x using First Principle of Derivatives

Derivative of e^x using First Principle of Derivatives

Using the first principle of derivatives, we will show that the derivative of e^x is e^x.

Proof. Let f(x) = e^x. We will be using the first principle derivative:
\begin{align*}
f'(x) &= \lim_{h \rightarrow 0} \frac{f(x+h) - f(x)}{h} \\
&= \lim_{h \rightarrow 0} \frac{e^{x+h} - e^x}{h} \\
&= \lim_{h \rightarrow 0} \frac{e^x(e^h - 1)}{h} \\
&= e^x \cdot \lim_{h \rightarrow 0} \frac{e^h - 1}{h}.
\end{align*}
We have seen here that \lim_{h \rightarrow 0} \frac{(e^h - 1)}{h} = 1. So we have that
\begin{align*}
f'(x) = e^x \cdot \lim_{h \rightarrow 0} \frac{e^h - 1}{h} = e^x,
\end{align*}
which proves that the derivative of e^x is e^x.

Leave a Reply