The integral of
xex2 is
21ex2+C.
Solution. We want to determine the integral of
xex2, i.e.:
∫xex2dx.
We will use the substitution method. Let
u=x2, then
du=2xdx. Therefore, we get:
∫xex2dx=21∫eudu=21eu+C=21ex2+C.
Therefore, the integral of
xex2 is
21ex2+C.