Derivative of Square Root x What is the Derivative of Square Root x? Post published:November 20, 2022 Post category:Calculus / Mathematics The derivative of x\sqrt{x}x is 12x\frac{1}{2\sqrt{x}}2x1. Solution. Let f(x)=xf(x) = \sqrt{x}f(x)=x. Then we can rewrite that as: f(x)=x=x1/2.\begin{align*} f(x) = \sqrt{x} = x^{1/2}. \end{align*}f(x)=x=x1/2. A simple fact from here says that ddxxn=nxn−1\frac{d}{dx} x^n = nx^{n-1}dxdxn=nxn−1. So we get: f′(x)=12x−12=12x.\begin{align*} f'(x) = \frac{1}{2}x^{-\frac{1}{2}} = \frac{1}{2\sqrt{x}}. \end{align*}f′(x)=21x−21=2x1. Therefore, the derivative of x\sqrt{x}x is 12x\frac{1}{2\sqrt{x}}2x1. Tags: Derivative of Square Root x, Square Root x You Might Also Like What is the integral of csc(x)? January 8, 2023 What are the Conjugacy Classes of Q8 October 16, 2022 Integral of 1/(x^2 – a^2) June 5, 2023 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Save my name, email, and website in this browser for the next time I comment.