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Derivative of sin^3(x)

What is the Derivative of sin^3(x)?

The derivative of \sin^3(x) is 3\sin^2(x)\cos(x).

Solution. Let F(x) = \sin^3(x), f(u) = u^3 and g(x) = \sin(x). We will use the chain rule:
\begin{align*}
F'(x) = f'(g(x))g'(x).
\end{align*}
We have seen here that \frac{d}{dx} \sin(x) = \cos(x), and \frac{d}{du} u^3 = 3u^2. So we get:
\begin{align*}
f'(u) = 3u^2 \quad \text{and} \quad g'(x) = \cos(x).
\end{align*}
Together, we get:
\begin{align*}
F'(x) &= f'(g(x))g'(x) \\
&= 3\sin^2(x)\cos(x).
\end{align*}
So, the derivative of \sin^3(x) is 3\sin^2(x)\cos(x).

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