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derivative of ln(x^2)

What is the derivative of ln(x^2)?

The derivative of \ln(x^2) is \frac{2}{x}.

Solution. Let h(x) = \ln(x^2), f(u) = \ln(u) and g(x) = x^2. We will apply that chain rule:
\begin{align*}
h'(x) = f'(g(x))g'(x).
\end{align*}
We do know that \frac{d}{dx} \ln(x) = \frac{1}{x} and that \frac{d}{dx} x^2 = 2x. So we get
\begin{align*}
f'(u) = \frac{1}{u} \quad \text{and} \quad g'(x) = 2x.
\end{align*}
Substituting everything together, we get
\begin{align*}
h'(x) &= f'(g(x))g'(x) \\
&= \frac{1}{x^2} \cdot 2x \\
&= \frac{2}{x}.
\end{align*}
So the derivative of \ln(x^2) is \frac{2}{x}.

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