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derivative of csc^3(x)

What is the derivative of csc^3(x)?

The derivative of \csc^3(x) is -3 \cot(x)\csc^3(x).

Solution. To determine the derivative of \csc^3(x), we will use the chain rule, i.e.:
\begin{align*}
F'(x) = f'(g(x))g'(x),
\end{align*}
where F(x) = f(g(x)) = \csc^3(x), f(u) = u^3 and g(x) = \csc(x). The derivative of f(u) = u^3 is f'(u) = 3u^2, and the derivative of g(x) = \csc(x) is g'(x) = -\cot(x)\csc(x), which we have seen here. Therefore, we get:
\begin{align*}
f'(g(x)) = f'(\csc(x)) = 3\csc^2(x) \quad \text{and} \quad g'(x) = -\cot(x)\csc(x).
\end{align*}
Combining everything, we get:
\begin{align*}
F'(x) &= f'(g(x))g'(x) \\
&= 3\csc^2(x) \cdot (-\cot(x)\csc(x)) \\
&= -3 \cot(x)\csc^3(x).
\end{align*}
Therefore, the derivative of \csc^3(x) is -3 \cot(x)\csc^3(x)

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