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derivative of tan^2(x)

What is the derivative of tan^2(x)?

We will determine the derivative of \tan^2(x).

Proof. Let F(x) = \tan^2(x), f(u) = u^2 and g(x) = \tan(x) such that F(x) = f(g(x)). We can use the chain rule
\begin{align*}
F'(x) = f'(g(x))g'(x).
\end{align*}
We know that \frac{d}{dx}\tan(x) = \sec^2(x) from this article, and f'(u) = 2u. Therefore:
\begin{align*}
f'(g(x)) = 2g(x) = 2\tan(x) \quad \text{and} \quad g'(x) = \sec^2(x).
\end{align*}
Combining everything, we get:
\begin{align*}
F(x) &= f'(g(x))g'(x) \\
&= 2\tan(x)\sec^2(x).
\end{align*}
which completes the proof. So the derivative of \tan^2(x) is 2\tan(x)\sec^2(x).

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